6(x+2)=5-3(x-5)

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Solution for 6(x+2)=5-3(x-5) equation:



6(x+2)=5-3(x-5)
We move all terms to the left:
6(x+2)-(5-3(x-5))=0
We multiply parentheses
6x-(5-3(x-5))+12=0
We calculate terms in parentheses: -(5-3(x-5)), so:
5-3(x-5)
determiningTheFunctionDomain -3(x-5)+5
We multiply parentheses
-3x+15+5
We add all the numbers together, and all the variables
-3x+20
Back to the equation:
-(-3x+20)
We get rid of parentheses
6x+3x-20+12=0
We add all the numbers together, and all the variables
9x-8=0
We move all terms containing x to the left, all other terms to the right
9x=8
x=8/9
x=8/9

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