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6(x+2)=2x+2(2x+3)
We move all terms to the left:
6(x+2)-(2x+2(2x+3))=0
We multiply parentheses
6x-(2x+2(2x+3))+12=0
We calculate terms in parentheses: -(2x+2(2x+3)), so:We get rid of parentheses
2x+2(2x+3)
We multiply parentheses
2x+4x+6
We add all the numbers together, and all the variables
6x+6
Back to the equation:
-(6x+6)
6x-6x-6+12=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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