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6(x+2)=2(x-5)
We move all terms to the left:
6(x+2)-(2(x-5))=0
We multiply parentheses
6x-(2(x-5))+12=0
We calculate terms in parentheses: -(2(x-5)), so:We get rid of parentheses
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
6x-2x+10+12=0
We add all the numbers together, and all the variables
4x+22=0
We move all terms containing x to the left, all other terms to the right
4x=-22
x=-22/4
x=-5+1/2
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