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6(x+2)=10(x-4)
We move all terms to the left:
6(x+2)-(10(x-4))=0
We multiply parentheses
6x-(10(x-4))+12=0
We calculate terms in parentheses: -(10(x-4)), so:We get rid of parentheses
10(x-4)
We multiply parentheses
10x-40
Back to the equation:
-(10x-40)
6x-10x+40+12=0
We add all the numbers together, and all the variables
-4x+52=0
We move all terms containing x to the left, all other terms to the right
-4x=-52
x=-52/-4
x=+13
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