6(x+2)-8=3x+3(1+x)

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Solution for 6(x+2)-8=3x+3(1+x) equation: 



6(x+2)-8=3x+3(1+x)

We move all terms to the left:

6(x+2)-8-(3x+3(1+x))=0

We add all the numbers together, and all the variables

6(x+2)-(3x+3(x+1))-8=0

We multiply parentheses

6x-(3x+3(x+1))+12-8=0



We calculate terms in parentheses: -(3x+3(x+1)), so:

3x+3(x+1)

We multiply parentheses

3x+3x+3

We add all the numbers together, and all the variables

6x+3

Back to the equation:

-(6x+3)



We add all the numbers together, and all the variables

6x-(6x+3)+4=0

We get rid of parentheses

6x-6x-3+4=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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