6(x+2)-4x=2(x-3)+18

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Solution for 6(x+2)-4x=2(x-3)+18 equation: 



6(x+2)-4x=2(x-3)+18

We move all terms to the left:

6(x+2)-4x-(2(x-3)+18)=0

We add all the numbers together, and all the variables

-4x+6(x+2)-(2(x-3)+18)=0

We multiply parentheses

-4x+6x-(2(x-3)+18)+12=0



We calculate terms in parentheses: -(2(x-3)+18), so:

2(x-3)+18

We multiply parentheses

2x-6+18

We add all the numbers together, and all the variables

2x+12

Back to the equation:

-(2x+12)



We add all the numbers together, and all the variables

2x-(2x+12)+12=0

We get rid of parentheses

2x-2x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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