6(x+2)-4(x+3)=7

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Solution for 6(x+2)-4(x+3)=7 equation: 



6(x+2)-4(x+3)=7

We move all terms to the left:

6(x+2)-4(x+3)-(7)=0

We multiply parentheses

6x-4x+12-12-7=0

We add all the numbers together, and all the variables

2x-7=0

We move all terms containing x to the left, all other terms to the right

2x=7

x=7/2

x=3+1/2

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