6(x+2)-3(x-3)=4(x-3)+2

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Solution for 6(x+2)-3(x-3)=4(x-3)+2 equation: 



6(x+2)-3(x-3)=4(x-3)+2

We move all terms to the left:

6(x+2)-3(x-3)-(4(x-3)+2)=0

We multiply parentheses

6x-3x-(4(x-3)+2)+12+9=0



We calculate terms in parentheses: -(4(x-3)+2), so:

4(x-3)+2

We multiply parentheses

4x-12+2

We add all the numbers together, and all the variables

4x-10

Back to the equation:

-(4x-10)



We add all the numbers together, and all the variables

3x-(4x-10)+21=0

We get rid of parentheses

3x-4x+10+21=0

We add all the numbers together, and all the variables

-1x+31=0

We move all terms containing x to the left, all other terms to the right

-x=-31

x=-31/-1

x=+31

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