6(x+2)-3(x+4)+3=2x+4(x+1)

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Solution for 6(x+2)-3(x+4)+3=2x+4(x+1) equation: 



6(x+2)-3(x+4)+3=2x+4(x+1)

We move all terms to the left:

6(x+2)-3(x+4)+3-(2x+4(x+1))=0

We multiply parentheses

6x-3x-(2x+4(x+1))+12-12+3=0



We calculate terms in parentheses: -(2x+4(x+1)), so:

2x+4(x+1)

We multiply parentheses

2x+4x+4

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

3x-(6x+4)+3=0

We get rid of parentheses

3x-6x-4+3=0

We add all the numbers together, and all the variables

-3x-1=0

We move all terms containing x to the left, all other terms to the right

-3x=1

x=1/-3

x=-1/3

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