6(x+2)+3=10(2x-4)+5.

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Solution for 6(x+2)+3=10(2x-4)+5. equation: 



6(x+2)+3=10(2x-4)+5.

We move all terms to the left:

6(x+2)+3-(10(2x-4)+5.)=0

We multiply parentheses

6x-(10(2x-4)+5.)+12+3=0



We calculate terms in parentheses: -(10(2x-4)+5.), so:

10(2x-4)+5.

We add all the numbers together, and all the variables

10(2x-4)+5

We multiply parentheses

20x-40+5

We add all the numbers together, and all the variables

20x-35

Back to the equation:

-(20x-35)



We add all the numbers together, and all the variables

6x-(20x-35)+15=0

We get rid of parentheses

6x-20x+35+15=0

We add all the numbers together, and all the variables

-14x+50=0

We move all terms containing x to the left, all other terms to the right

-14x=-50

x=-50/-14

x=3+4/7

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