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6(x+2)+2x-4=8x-16+8
We move all terms to the left:
6(x+2)+2x-4-(8x-16+8)=0
We add all the numbers together, and all the variables
6(x+2)+2x-(8x-8)-4=0
We add all the numbers together, and all the variables
2x+6(x+2)-(8x-8)-4=0
We multiply parentheses
2x+6x-(8x-8)+12-4=0
We get rid of parentheses
2x+6x-8x+8+12-4=0
We add all the numbers together, and all the variables
16!=0
There is no solution for this equation
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