6(x+2)+2x-4=8(x-2)+4

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Solution for 6(x+2)+2x-4=8(x-2)+4 equation:


Simplifying
6(x + 2) + 2x + -4 = 8(x + -2) + 4

Reorder the terms:
6(2 + x) + 2x + -4 = 8(x + -2) + 4
(2 * 6 + x * 6) + 2x + -4 = 8(x + -2) + 4
(12 + 6x) + 2x + -4 = 8(x + -2) + 4

Reorder the terms:
12 + -4 + 6x + 2x = 8(x + -2) + 4

Combine like terms: 12 + -4 = 8
8 + 6x + 2x = 8(x + -2) + 4

Combine like terms: 6x + 2x = 8x
8 + 8x = 8(x + -2) + 4

Reorder the terms:
8 + 8x = 8(-2 + x) + 4
8 + 8x = (-2 * 8 + x * 8) + 4
8 + 8x = (-16 + 8x) + 4

Reorder the terms:
8 + 8x = -16 + 4 + 8x

Combine like terms: -16 + 4 = -12
8 + 8x = -12 + 8x

Add '-8x' to each side of the equation.
8 + 8x + -8x = -12 + 8x + -8x

Combine like terms: 8x + -8x = 0
8 + 0 = -12 + 8x + -8x
8 = -12 + 8x + -8x

Combine like terms: 8x + -8x = 0
8 = -12 + 0
8 = -12

Solving
8 = -12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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