6(x+2)+2x-4=(x-2)+8

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Solution for 6(x+2)+2x-4=(x-2)+8 equation: 



6(x+2)+2x-4=(x-2)+8

We move all terms to the left:

6(x+2)+2x-4-((x-2)+8)=0

We add all the numbers together, and all the variables

2x+6(x+2)-((x-2)+8)-4=0

We multiply parentheses

2x+6x-((x-2)+8)+12-4=0



We calculate terms in parentheses: -((x-2)+8), so:

(x-2)+8

We get rid of parentheses

x-2+8

We add all the numbers together, and all the variables

x+6

Back to the equation:

-(x+6)



We add all the numbers together, and all the variables

8x-(x+6)+8=0

We get rid of parentheses

8x-x-6+8=0

We add all the numbers together, and all the variables

7x+2=0

We move all terms containing x to the left, all other terms to the right

7x=-2

x=-2/7

x=-2/7

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