6(x+12)-7=4(3x-6)+2

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Solution for 6(x+12)-7=4(3x-6)+2 equation: 



6(x+12)-7=4(3x-6)+2

We move all terms to the left:

6(x+12)-7-(4(3x-6)+2)=0

We multiply parentheses

6x-(4(3x-6)+2)+72-7=0



We calculate terms in parentheses: -(4(3x-6)+2), so:

4(3x-6)+2

We multiply parentheses

12x-24+2

We add all the numbers together, and all the variables

12x-22

Back to the equation:

-(12x-22)



We add all the numbers together, and all the variables

6x-(12x-22)+65=0

We get rid of parentheses

6x-12x+22+65=0

We add all the numbers together, and all the variables

-6x+87=0

We move all terms containing x to the left, all other terms to the right

-6x=-87

x=-87/-6

x=14+1/2

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