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6(x+10)=3(2x+4)-2
We move all terms to the left:
6(x+10)-(3(2x+4)-2)=0
We multiply parentheses
6x-(3(2x+4)-2)+60=0
We calculate terms in parentheses: -(3(2x+4)-2), so:We get rid of parentheses
3(2x+4)-2
We multiply parentheses
6x+12-2
We add all the numbers together, and all the variables
6x+10
Back to the equation:
-(6x+10)
6x-6x-10+60=0
We add all the numbers together, and all the variables
50!=0
There is no solution for this equation
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