6(x+10)+x=4(x+4)-8

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Solution for 6(x+10)+x=4(x+4)-8 equation: 



6(x+10)+x=4(x+4)-8

We move all terms to the left:

6(x+10)+x-(4(x+4)-8)=0

We add all the numbers together, and all the variables

x+6(x+10)-(4(x+4)-8)=0

We multiply parentheses

x+6x-(4(x+4)-8)+60=0



We calculate terms in parentheses: -(4(x+4)-8), so:

4(x+4)-8

We multiply parentheses

4x+16-8

We add all the numbers together, and all the variables

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

7x-(4x+8)+60=0

We get rid of parentheses

7x-4x-8+60=0

We add all the numbers together, and all the variables

3x+52=0

We move all terms containing x to the left, all other terms to the right

3x=-52

x=-52/3

x=-17+1/3

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