6(x+1)=3(2x+1)+3

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Solution for 6(x+1)=3(2x+1)+3 equation: 



6(x+1)=3(2x+1)+3

We move all terms to the left:

6(x+1)-(3(2x+1)+3)=0

We multiply parentheses

6x-(3(2x+1)+3)+6=0



We calculate terms in parentheses: -(3(2x+1)+3), so:

3(2x+1)+3

We multiply parentheses

6x+3+3

We add all the numbers together, and all the variables

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

6x-6x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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