6(x+1)=3(1+x)

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Solution for 6(x+1)=3(1+x) equation: 



6(x+1)=3(1+x)

We move all terms to the left:

6(x+1)-(3(1+x))=0

We add all the numbers together, and all the variables

6(x+1)-(3(x+1))=0

We multiply parentheses

6x-(3(x+1))+6=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

6x-3x-3+6=0

We add all the numbers together, and all the variables

3x+3=0

We move all terms containing x to the left, all other terms to the right

3x=-3

x=-3/3

x=-1

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