6(x+1)-5x=8+(2x-1)

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Solution for 6(x+1)-5x=8+(2x-1) equation: 



6(x+1)-5x=8+(2x-1)

We move all terms to the left:

6(x+1)-5x-(8+(2x-1))=0

We add all the numbers together, and all the variables

-5x+6(x+1)-(8+(2x-1))=0

We multiply parentheses

-5x+6x-(8+(2x-1))+6=0



We calculate terms in parentheses: -(8+(2x-1)), so:

8+(2x-1)

determiningTheFunctionDomain
(2x-1)+8

We get rid of parentheses

2x-1+8

We add all the numbers together, and all the variables

2x+7

Back to the equation:

-(2x+7)



We add all the numbers together, and all the variables

x-(2x+7)+6=0

We get rid of parentheses

x-2x-7+6=0

We add all the numbers together, and all the variables

-1x-1=0

We move all terms containing x to the left, all other terms to the right

-x=1

x=1/-1

x=-1

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