6(x+1)-3x=8(2x-1)

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Solution for 6(x+1)-3x=8(2x-1) equation: 



6(x+1)-3x=8(2x-1)

We move all terms to the left:

6(x+1)-3x-(8(2x-1))=0

We add all the numbers together, and all the variables

-3x+6(x+1)-(8(2x-1))=0

We multiply parentheses

-3x+6x-(8(2x-1))+6=0



We calculate terms in parentheses: -(8(2x-1)), so:

8(2x-1)

We multiply parentheses

16x-8

Back to the equation:

-(16x-8)



We add all the numbers together, and all the variables

3x-(16x-8)+6=0

We get rid of parentheses

3x-16x+8+6=0

We add all the numbers together, and all the variables

-13x+14=0

We move all terms containing x to the left, all other terms to the right

-13x=-14

x=-14/-13

x=1+1/13

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