6(x+1)-3(x-2)=x+4

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Solution for 6(x+1)-3(x-2)=x+4 equation: 



6(x+1)-3(x-2)=x+4

We move all terms to the left:

6(x+1)-3(x-2)-(x+4)=0

We multiply parentheses

6x-3x-(x+4)+6+6=0

We get rid of parentheses

6x-3x-x-4+6+6=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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