6(x+1)-2x-1=(x+15)(x+16)

Solution for 6(x+1)-2x-1=(x+15)(x+16) equation:

6(x+1)-2x-1=(x+15)(x+16)

We move all terms to the left:

6(x+1)-2x-1-((x+15)(x+16))=0

We add all the numbers together, and all the variables

-2x+6(x+1)-((x+15)(x+16))-1=0

We multiply parentheses

-2x+6x-((x+15)(x+16))+6-1=0

We multiply parentheses ..

-((+x^2+16x+15x+240))-2x+6x+6-1=0


We calculate terms in parentheses: -((+x^2+16x+15x+240)), so:

(+x^2+16x+15x+240)

We get rid of parentheses

x^2+16x+15x+240

We add all the numbers together, and all the variables

x^2+31x+240

Back to the equation:

-(x^2+31x+240)


We add all the numbers together, and all the variables

4x-(x^2+31x+240)+5=0

We get rid of parentheses

-x^2+4x-31x-240+5=0

We add all the numbers together, and all the variables

-1x^2-27x-235=0

a = -1; b = -27; c = -235;
Δ = b2-4ac
Δ = -272-4·(-1)·(-235)
Δ = -211
Delta is less than zero, so there is no solution for the equation