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6(x+1)-10=4(x-1))+2x
We move all terms to the left:
6(x+1)-10-(4(x-1))+2x)=0
We multiply parentheses
6x-(4(x-1))+2x)-10+6=0
We calculate terms in parentheses: -(4(x-1)), so:We get rid of parentheses
4(x-1)
We multiply parentheses
4x-4
Back to the equation:
-(4x-4)
6x-4x+2x)-10+6+4=0
We add all the numbers together, and all the variables
2x+2x)-10+6+4=0
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