6(x+1)+5=13-(2+6x)

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Solution for 6(x+1)+5=13-(2+6x) equation: 



6(x+1)+5=13-(2+6x)

We move all terms to the left:

6(x+1)+5-(13-(2+6x))=0

We add all the numbers together, and all the variables

6(x+1)-(13-(6x+2))+5=0

We multiply parentheses

6x-(13-(6x+2))+6+5=0



We calculate terms in parentheses: -(13-(6x+2)), so:

13-(6x+2)

determiningTheFunctionDomain
-(6x+2)+13

We get rid of parentheses

-6x-2+13

We add all the numbers together, and all the variables

-6x+11

Back to the equation:

-(-6x+11)



We add all the numbers together, and all the variables

6x-(-6x+11)+11=0

We get rid of parentheses

6x+6x-11+11=0

We add all the numbers together, and all the variables

12x=0

x=0/12

x=0

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