6(x+1)+4(x+2)=36-3(x+3)

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Solution for 6(x+1)+4(x+2)=36-3(x+3) equation: 



6(x+1)+4(x+2)=36-3(x+3)

We move all terms to the left:

6(x+1)+4(x+2)-(36-3(x+3))=0

We multiply parentheses

6x+4x-(36-3(x+3))+6+8=0



We calculate terms in parentheses: -(36-3(x+3)), so:

36-3(x+3)

determiningTheFunctionDomain
-3(x+3)+36

We multiply parentheses

-3x-9+36

We add all the numbers together, and all the variables

-3x+27

Back to the equation:

-(-3x+27)



We add all the numbers together, and all the variables

10x-(-3x+27)+14=0

We get rid of parentheses

10x+3x-27+14=0

We add all the numbers together, and all the variables

13x-13=0

We move all terms containing x to the left, all other terms to the right

13x=13

x=13/13

x=1

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