6(w-2)+1=2(3-w)-5

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Solution for 6(w-2)+1=2(3-w)-5 equation: 



6(w-2)+1=2(3-w)-5

We move all terms to the left:

6(w-2)+1-(2(3-w)-5)=0

We add all the numbers together, and all the variables

6(w-2)-(2(-1w+3)-5)+1=0

We multiply parentheses

6w-(2(-1w+3)-5)-12+1=0



We calculate terms in parentheses: -(2(-1w+3)-5), so:

2(-1w+3)-5

We multiply parentheses

-2w+6-5

We add all the numbers together, and all the variables

-2w+1

Back to the equation:

-(-2w+1)



We add all the numbers together, and all the variables

6w-(-2w+1)-11=0

We get rid of parentheses

6w+2w-1-11=0

We add all the numbers together, and all the variables

8w-12=0

We move all terms containing w to the left, all other terms to the right

8w=12

w=12/8

w=1+1/2

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