6(v-5)-2=-7(-3v+4)-9v

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Solution for 6(v-5)-2=-7(-3v+4)-9v equation: 



6(v-5)-2=-7(-3v+4)-9v

We move all terms to the left:

6(v-5)-2-(-7(-3v+4)-9v)=0

We multiply parentheses

6v-(-7(-3v+4)-9v)-30-2=0



We calculate terms in parentheses: -(-7(-3v+4)-9v), so:

-7(-3v+4)-9v

We add all the numbers together, and all the variables

-9v-7(-3v+4)

We multiply parentheses

-9v+21v-28

We add all the numbers together, and all the variables

12v-28

Back to the equation:

-(12v-28)



We add all the numbers together, and all the variables

6v-(12v-28)-32=0

We get rid of parentheses

6v-12v+28-32=0

We add all the numbers together, and all the variables

-6v-4=0

We move all terms containing v to the left, all other terms to the right

-6v=4

v=4/-6

v=-2/3

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