6(v-2)+2=(3v-5)

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Solution for 6(v-2)+2=(3v-5) equation: 



6(v-2)+2=(3v-5)

We move all terms to the left:

6(v-2)+2-((3v-5))=0

We multiply parentheses

6v-((3v-5))-12+2=0



We calculate terms in parentheses: -((3v-5)), so:

(3v-5)

We get rid of parentheses

3v-5

Back to the equation:

-(3v-5)



We add all the numbers together, and all the variables

6v-(3v-5)-10=0

We get rid of parentheses

6v-3v+5-10=0

We add all the numbers together, and all the variables

3v-5=0

We move all terms containing v to the left, all other terms to the right

3v=5

v=5/3

v=1+2/3

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