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6(v-1)-10=4(v-1)+2v
We move all terms to the left:
6(v-1)-10-(4(v-1)+2v)=0
We multiply parentheses
6v-(4(v-1)+2v)-6-10=0
We calculate terms in parentheses: -(4(v-1)+2v), so:We add all the numbers together, and all the variables
4(v-1)+2v
We add all the numbers together, and all the variables
2v+4(v-1)
We multiply parentheses
2v+4v-4
We add all the numbers together, and all the variables
6v-4
Back to the equation:
-(6v-4)
6v-(6v-4)-16=0
We get rid of parentheses
6v-6v+4-16=0
We add all the numbers together, and all the variables
-12!=0
There is no solution for this equation
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