6(v+2)=2v+48

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Solution for 6(v+2)=2v+48 equation: 



6(v+2)=2v+48

We move all terms to the left:

6(v+2)-(2v+48)=0

We multiply parentheses

6v-(2v+48)+12=0

We get rid of parentheses

6v-2v-48+12=0

We add all the numbers together, and all the variables

4v-36=0

We move all terms containing v to the left, all other terms to the right

4v=36

v=36/4

v=9

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