6(u+3)=-2(4u-2)+6u

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Solution for 6(u+3)=-2(4u-2)+6u equation: 



6(u+3)=-2(4u-2)+6u

We move all terms to the left:

6(u+3)-(-2(4u-2)+6u)=0

We multiply parentheses

6u-(-2(4u-2)+6u)+18=0



We calculate terms in parentheses: -(-2(4u-2)+6u), so:

-2(4u-2)+6u

We add all the numbers together, and all the variables

6u-2(4u-2)

We multiply parentheses

6u-8u+4

We add all the numbers together, and all the variables

-2u+4

Back to the equation:

-(-2u+4)



We get rid of parentheses

6u+2u-4+18=0

We add all the numbers together, and all the variables

8u+14=0

We move all terms containing u to the left, all other terms to the right

8u=-14

u=-14/8

u=-1+3/4

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