6(u+2)=3u+24

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Solution for 6(u+2)=3u+24 equation: 



6(u+2)=3u+24

We move all terms to the left:

6(u+2)-(3u+24)=0

We multiply parentheses

6u-(3u+24)+12=0

We get rid of parentheses

6u-3u-24+12=0

We add all the numbers together, and all the variables

3u-12=0

We move all terms containing u to the left, all other terms to the right

3u=12

u=12/3

u=4

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