6(u+2)=-4(2u-1)+2u

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Solution for 6(u+2)=-4(2u-1)+2u equation: 



6(u+2)=-4(2u-1)+2u

We move all terms to the left:

6(u+2)-(-4(2u-1)+2u)=0

We multiply parentheses

6u-(-4(2u-1)+2u)+12=0



We calculate terms in parentheses: -(-4(2u-1)+2u), so:

-4(2u-1)+2u

We add all the numbers together, and all the variables

2u-4(2u-1)

We multiply parentheses

2u-8u+4

We add all the numbers together, and all the variables

-6u+4

Back to the equation:

-(-6u+4)



We get rid of parentheses

6u+6u-4+12=0

We add all the numbers together, and all the variables

12u+8=0

We move all terms containing u to the left, all other terms to the right

12u=-8

u=-8/12

u=-2/3

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