6(u+1)=2u+38

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Solution for 6(u+1)=2u+38 equation: 



6(u+1)=2u+38

We move all terms to the left:

6(u+1)-(2u+38)=0

We multiply parentheses

6u-(2u+38)+6=0

We get rid of parentheses

6u-2u-38+6=0

We add all the numbers together, and all the variables

4u-32=0

We move all terms containing u to the left, all other terms to the right

4u=32

u=32/4

u=8

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