6(u+1)=-3(5u-5)+3u

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Solution for 6(u+1)=-3(5u-5)+3u equation:



6(u+1)=-3(5u-5)+3u
We move all terms to the left:
6(u+1)-(-3(5u-5)+3u)=0
We multiply parentheses
6u-(-3(5u-5)+3u)+6=0
We calculate terms in parentheses: -(-3(5u-5)+3u), so:
-3(5u-5)+3u
We add all the numbers together, and all the variables
3u-3(5u-5)
We multiply parentheses
3u-15u+15
We add all the numbers together, and all the variables
-12u+15
Back to the equation:
-(-12u+15)
We get rid of parentheses
6u+12u-15+6=0
We add all the numbers together, and all the variables
18u-9=0
We move all terms containing u to the left, all other terms to the right
18u=9
u=9/18
u=1/2

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