6(u+1)-10=4(u-1)+2u

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Solution for 6(u+1)-10=4(u-1)+2u equation:


Simplifying
6(u + 1) + -10 = 4(u + -1) + 2u

Reorder the terms:
6(1 + u) + -10 = 4(u + -1) + 2u
(1 * 6 + u * 6) + -10 = 4(u + -1) + 2u
(6 + 6u) + -10 = 4(u + -1) + 2u

Reorder the terms:
6 + -10 + 6u = 4(u + -1) + 2u

Combine like terms: 6 + -10 = -4
-4 + 6u = 4(u + -1) + 2u

Reorder the terms:
-4 + 6u = 4(-1 + u) + 2u
-4 + 6u = (-1 * 4 + u * 4) + 2u
-4 + 6u = (-4 + 4u) + 2u

Combine like terms: 4u + 2u = 6u
-4 + 6u = -4 + 6u

Add '4' to each side of the equation.
-4 + 4 + 6u = -4 + 4 + 6u

Combine like terms: -4 + 4 = 0
0 + 6u = -4 + 4 + 6u
6u = -4 + 4 + 6u

Combine like terms: -4 + 4 = 0
6u = 0 + 6u
6u = 6u

Add '-6u' to each side of the equation.
6u + -6u = 6u + -6u

Combine like terms: 6u + -6u = 0
0 = 6u + -6u

Combine like terms: 6u + -6u = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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