6(t+2)=(2+t)6

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Solution for 6(t+2)=(2+t)6 equation: 



6(t+2)=(2+t)6

We move all terms to the left:

6(t+2)-((2+t)6)=0

We add all the numbers together, and all the variables

6(t+2)-((t+2)6)=0

We multiply parentheses

6t-((t+2)6)+12=0



We calculate terms in parentheses: -((t+2)6), so:

(t+2)6

We multiply parentheses

6t+12

Back to the equation:

-(6t+12)



We get rid of parentheses

6t-6t-12+12=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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