6(r-9)=2(r-11)

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Solution for 6(r-9)=2(r-11) equation: 



6(r-9)=2(r-11)

We move all terms to the left:

6(r-9)-(2(r-11))=0

We multiply parentheses

6r-(2(r-11))-54=0



We calculate terms in parentheses: -(2(r-11)), so:

2(r-11)

We multiply parentheses

2r-22

Back to the equation:

-(2r-22)



We get rid of parentheses

6r-2r+22-54=0

We add all the numbers together, and all the variables

4r-32=0

We move all terms containing r to the left, all other terms to the right

4r=32

r=32/4

r=8

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