6(r-4)=5(r+-7)

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Solution for 6(r-4)=5(r+-7) equation: 



6(r-4)=5(r+-7)

We move all terms to the left:

6(r-4)-(5(r+-7))=0

We add all the numbers together, and all the variables

6(r-4)-(5(r-7))=0

We multiply parentheses

6r-(5(r-7))-24=0



We calculate terms in parentheses: -(5(r-7)), so:

5(r-7)

We multiply parentheses

5r-35

Back to the equation:

-(5r-35)



We get rid of parentheses

6r-5r+35-24=0

We add all the numbers together, and all the variables

r+11=0

We move all terms containing r to the left, all other terms to the right

r=-11

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