6(p-2)-3(p-1)=p+1

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Solution for 6(p-2)-3(p-1)=p+1 equation: 



6(p-2)-3(p-1)=p+1

We move all terms to the left:

6(p-2)-3(p-1)-(p+1)=0

We multiply parentheses

6p-3p-(p+1)-12+3=0

We get rid of parentheses

6p-3p-p-1-12+3=0

We add all the numbers together, and all the variables

2p-10=0

We move all terms containing p to the left, all other terms to the right

2p=10

p=10/2

p=5

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