6(p-1)-p=-2(p+2)+p-1

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Solution for 6(p-1)-p=-2(p+2)+p-1 equation: 



6(p-1)-p=-2(p+2)+p-1

We move all terms to the left:

6(p-1)-p-(-2(p+2)+p-1)=0

We add all the numbers together, and all the variables

-1p+6(p-1)-(-2(p+2)+p-1)=0

We multiply parentheses

-1p+6p-(-2(p+2)+p-1)-6=0



We calculate terms in parentheses: -(-2(p+2)+p-1), so:

-2(p+2)+p-1

We add all the numbers together, and all the variables

p-2(p+2)-1

We multiply parentheses

p-2p-4-1

We add all the numbers together, and all the variables

-1p-5

Back to the equation:

-(-1p-5)



We add all the numbers together, and all the variables

5p-(-1p-5)-6=0

We get rid of parentheses

5p+1p+5-6=0

We add all the numbers together, and all the variables

6p-1=0

We move all terms containing p to the left, all other terms to the right

6p=1

p=1/6

p=1/6

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