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6(n-5)=3(n-1)
We move all terms to the left:
6(n-5)-(3(n-1))=0
We multiply parentheses
6n-(3(n-1))-30=0
We calculate terms in parentheses: -(3(n-1)), so:We get rid of parentheses
3(n-1)
We multiply parentheses
3n-3
Back to the equation:
-(3n-3)
6n-3n+3-30=0
We add all the numbers together, and all the variables
3n-27=0
We move all terms containing n to the left, all other terms to the right
3n=27
n=27/3
n=9
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