6(n-4)=8(2n+3)

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Solution for 6(n-4)=8(2n+3) equation: 



6(n-4)=8(2n+3)

We move all terms to the left:

6(n-4)-(8(2n+3))=0

We multiply parentheses

6n-(8(2n+3))-24=0



We calculate terms in parentheses: -(8(2n+3)), so:

8(2n+3)

We multiply parentheses

16n+24

Back to the equation:

-(16n+24)



We get rid of parentheses

6n-16n-24-24=0

We add all the numbers together, and all the variables

-10n-48=0

We move all terms containing n to the left, all other terms to the right

-10n=48

n=48/-10

n=-4+4/5

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