6(n-4)=2(2n-7)

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Solution for 6(n-4)=2(2n-7) equation: 



6(n-4)=2(2n-7)

We move all terms to the left:

6(n-4)-(2(2n-7))=0

We multiply parentheses

6n-(2(2n-7))-24=0



We calculate terms in parentheses: -(2(2n-7)), so:

2(2n-7)

We multiply parentheses

4n-14

Back to the equation:

-(4n-14)



We get rid of parentheses

6n-4n+14-24=0

We add all the numbers together, and all the variables

2n-10=0

We move all terms containing n to the left, all other terms to the right

2n=10

n=10/2

n=5

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