6(n-2)-3n-1=8(5n+1)-10n

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Solution for 6(n-2)-3n-1=8(5n+1)-10n equation: 



6(n-2)-3n-1=8(5n+1)-10n

We move all terms to the left:

6(n-2)-3n-1-(8(5n+1)-10n)=0

We add all the numbers together, and all the variables

-3n+6(n-2)-(8(5n+1)-10n)-1=0

We multiply parentheses

-3n+6n-(8(5n+1)-10n)-12-1=0



We calculate terms in parentheses: -(8(5n+1)-10n), so:

8(5n+1)-10n

We add all the numbers together, and all the variables

-10n+8(5n+1)

We multiply parentheses

-10n+40n+8

We add all the numbers together, and all the variables

30n+8

Back to the equation:

-(30n+8)



We add all the numbers together, and all the variables

3n-(30n+8)-13=0

We get rid of parentheses

3n-30n-8-13=0

We add all the numbers together, and all the variables

-27n-21=0

We move all terms containing n to the left, all other terms to the right

-27n=21

n=21/-27

n=-7/9

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