6(n-2)+3=9n-15

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Solution for 6(n-2)+3=9n-15 equation: 



6(n-2)+3=9n-15

We move all terms to the left:

6(n-2)+3-(9n-15)=0

We multiply parentheses

6n-(9n-15)-12+3=0

We get rid of parentheses

6n-9n+15-12+3=0

We add all the numbers together, and all the variables

-3n+6=0

We move all terms containing n to the left, all other terms to the right

-3n=-6

n=-6/-3

n=+2

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