6(n+7)=4+5(2n+6)

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Solution for 6(n+7)=4+5(2n+6) equation: 



6(n+7)=4+5(2n+6)

We move all terms to the left:

6(n+7)-(4+5(2n+6))=0

We multiply parentheses

6n-(4+5(2n+6))+42=0



We calculate terms in parentheses: -(4+5(2n+6)), so:

4+5(2n+6)

determiningTheFunctionDomain
5(2n+6)+4

We multiply parentheses

10n+30+4

We add all the numbers together, and all the variables

10n+34

Back to the equation:

-(10n+34)



We get rid of parentheses

6n-10n-34+42=0

We add all the numbers together, and all the variables

-4n+8=0

We move all terms containing n to the left, all other terms to the right

-4n=-8

n=-8/-4

n=+2

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