6(n+3)=2(3n+1)

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Solution for 6(n+3)=2(3n+1) equation: 



6(n+3)=2(3n+1)

We move all terms to the left:

6(n+3)-(2(3n+1))=0

We multiply parentheses

6n-(2(3n+1))+18=0



We calculate terms in parentheses: -(2(3n+1)), so:

2(3n+1)

We multiply parentheses

6n+2

Back to the equation:

-(6n+2)



We get rid of parentheses

6n-6n-2+18=0

We add all the numbers together, and all the variables

16!=0

There is no solution for this equation

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