6(n+3)-2=4n+2(n+4)+8

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Solution for 6(n+3)-2=4n+2(n+4)+8 equation: 



6(n+3)-2=4n+2(n+4)+8

We move all terms to the left:

6(n+3)-2-(4n+2(n+4)+8)=0

We multiply parentheses

6n-(4n+2(n+4)+8)+18-2=0



We calculate terms in parentheses: -(4n+2(n+4)+8), so:

4n+2(n+4)+8

We multiply parentheses

4n+2n+8+8

We add all the numbers together, and all the variables

6n+16

Back to the equation:

-(6n+16)



We add all the numbers together, and all the variables

6n-(6n+16)+16=0

We get rid of parentheses

6n-6n-16+16=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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