6(n+3)+2(2n-4)=3(n+8)

Solution for 6(n+3)+2(2n-4)=3(n+8) equation:

6(n+3)+2(2n-4)=3(n+8)

We move all terms to the left:

6(n+3)+2(2n-4)-(3(n+8))=0

We multiply parentheses

6n+4n-(3(n+8))+18-8=0


We calculate terms in parentheses: -(3(n+8)), so:

3(n+8)

We multiply parentheses

3n+24

Back to the equation:

-(3n+24)


We add all the numbers together, and all the variables

10n-(3n+24)+10=0

We get rid of parentheses

10n-3n-24+10=0

We add all the numbers together, and all the variables

7n-14=0

We move all terms containing n to the left, all other terms to the right

7n=14

n=14/7

n=2